Base | Representation |
---|---|
bin | 11000101100001000… |
… | …10111001001000011 |
3 | 1021012202220002020101 |
4 | 30112010113021003 |
5 | 204121304102003 |
6 | 10031143423231 |
7 | 646321602463 |
oct | 142604271103 |
9 | 37182802211 |
10 | 13255144003 |
11 | 5692201972 |
12 | 269b154b17 |
13 | 13331c589a |
14 | 8da5c3ba3 |
15 | 528a5011d |
hex | 316117243 |
13255144003 has 2 divisors, whose sum is σ = 13255144004. Its totient is φ = 13255144002.
The previous prime is 13255143991. The next prime is 13255144013. The reversal of 13255144003 is 30044155231.
It is a strong prime.
It is an emirp because it is prime and its reverse (30044155231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13255144003 - 25 = 13255143971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13255144013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627572001 + 6627572002.
It is an arithmetic number, because the mean of its divisors is an integer number (6627572002).
Almost surely, 213255144003 is an apocalyptic number.
13255144003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13255144003 is an equidigital number, since it uses as much as digits as its factorization.
13255144003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 13255144003 its reverse (30044155231), we get a palindrome (43299299234).
The spelling of 13255144003 in words is "thirteen billion, two hundred fifty-five million, one hundred forty-four thousand, three".
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