13255222141034 has 4 divisors (see below), whose sum is σ = 19882833211554. Its totient is φ = 6627611070516.

The previous prime is 13255222140977. The next prime is 13255222141043. The reversal of 13255222141034 is 43014122255231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12675344460025 + 579877681009 = 3560245^2 + 761497^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13255222140985 and 13255222141003.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3313805535257 + ... + 3313805535260.

Almost surely, 2^{13255222141034} is an apocalyptic number.

13255222141034 is a deficient number, since it is larger than the sum of its proper divisors (6627611070520).

13255222141034 is an equidigital number, since it uses as much as digits as its factorization.

13255222141034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6627611070519.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 13255222141034 its reverse (43014122255231), we get a palindrome (56269344396265).

The spelling of 13255222141034 in words is "thirteen trillion, two hundred fifty-five billion, two hundred twenty-two million, one hundred forty-one thousand, thirty-four".