Base | Representation |
---|---|
bin | 11110001000111001110101… |
… | …100000011011010110000001 |
3 | 122101022222010001100001002112 |
4 | 132020321311200123112001 |
5 | 114333223030020432113 |
6 | 1145530042352025105 |
7 | 36630441104524136 |
oct | 3610716540332601 |
9 | 571288101301075 |
10 | 132553252124033 |
11 | 39265578193474 |
12 | 12a4985bb32195 |
13 | 58c69446c5990 |
14 | 24a387c47858d |
15 | 104d0332e65a8 |
hex | 788e7581b581 |
132553252124033 has 16 divisors (see below), whose sum is σ = 143913153384000. Its totient is φ = 121360523269440.
The previous prime is 132553252124017. The next prime is 132553252124039. The reversal of 132553252124033 is 330421252355231.
It is not a de Polignac number, because 132553252124033 - 24 = 132553252124017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132553252124039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16648823 + ... + 23287116.
It is an arithmetic number, because the mean of its divisors is an integer number (8994572086500).
Almost surely, 2132553252124033 is an apocalyptic number.
132553252124033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
132553252124033 is a deficient number, since it is larger than the sum of its proper divisors (11359901259967).
132553252124033 is a wasteful number, since it uses less digits than its factorization.
132553252124033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39938032.
The product of its (nonzero) digits is 648000, while the sum is 41.
The spelling of 132553252124033 in words is "one hundred thirty-two trillion, five hundred fifty-three billion, two hundred fifty-two million, one hundred twenty-four thousand, thirty-three".
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