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13255545245147 is a prime number
BaseRepresentation
bin1100000011100100110000…
…0100001100110111011011
31201221012212201222000200122
43000321030010030313123
53214134324040321042
644105302522023455
72535452524344542
oct300711404146733
951835781860618
1013255545245147
1142507107a0777
1215a101b347b8b
13751cb984004a
1433b8010ab159
1517ec1920b7d2
hexc0e4c10cddb

13255545245147 has 2 divisors, whose sum is σ = 13255545245148. Its totient is φ = 13255545245146.

The previous prime is 13255545245113. The next prime is 13255545245153. The reversal of 13255545245147 is 74154254555231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13255545245147 - 232 = 13251250277851 is a prime.

It is a super-2 number, since 2×132555452451472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13255545245647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627772622573 + 6627772622574.

It is an arithmetic number, because the mean of its divisors is an integer number (6627772622574).

Almost surely, 213255545245147 is an apocalyptic number.

13255545245147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13255545245147 is an equidigital number, since it uses as much as digits as its factorization.

13255545245147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 16800000, while the sum is 53.

The spelling of 13255545245147 in words is "thirteen trillion, two hundred fifty-five billion, five hundred forty-five million, two hundred forty-five thousand, one hundred forty-seven".