Base | Representation |
---|---|
bin | 111101101110011101… |
… | …1001010010100100011 |
3 | 110200011000120212101212 |
4 | 1323130323022110203 |
5 | 4132433202441141 |
6 | 140521204420335 |
7 | 12401564200622 |
oct | 1733473122443 |
9 | 420130525355 |
10 | 132555515171 |
11 | 51242150542 |
12 | 218346a76ab |
13 | c6664707a1 |
14 | 65b6a4b6b9 |
15 | 36ac3a82eb |
hex | 1edceca523 |
132555515171 has 2 divisors, whose sum is σ = 132555515172. Its totient is φ = 132555515170.
The previous prime is 132555515153. The next prime is 132555515201. The reversal of 132555515171 is 171515555231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132555515171 - 218 = 132555253027 is a prime.
It is a super-2 number, since 2×1325555151712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132555515671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66277757585 + 66277757586.
It is an arithmetic number, because the mean of its divisors is an integer number (66277757586).
Almost surely, 2132555515171 is an apocalyptic number.
132555515171 is a deficient number, since it is larger than the sum of its proper divisors (1).
132555515171 is an equidigital number, since it uses as much as digits as its factorization.
132555515171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 131250, while the sum is 41.
The spelling of 132555515171 in words is "one hundred thirty-two billion, five hundred fifty-five million, five hundred fifteen thousand, one hundred seventy-one".
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