Base | Representation |
---|---|
bin | 10011010010100100000… |
… | …000110110001010101001 |
3 | 11200201121110022010011221 |
4 | 103102210000312022221 |
5 | 133204313003044312 |
6 | 2452550055022041 |
7 | 164525433536053 |
oct | 23224400661251 |
9 | 4621543263157 |
10 | 1325601612457 |
11 | 4712036085a1 |
12 | 194ab136a921 |
13 | 98008172455 |
14 | 482337b88d3 |
15 | 24736833207 |
hex | 134a40362a9 |
1325601612457 has 2 divisors, whose sum is σ = 1325601612458. Its totient is φ = 1325601612456.
The previous prime is 1325601612449. The next prime is 1325601612529. The reversal of 1325601612457 is 7542161065231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1219469655616 + 106131956841 = 1104296^2 + 325779^2 .
It is a cyclic number.
It is not a de Polignac number, because 1325601612457 - 23 = 1325601612449 is a prime.
It is not a weakly prime, because it can be changed into another prime (1325601612407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662800806228 + 662800806229.
It is an arithmetic number, because the mean of its divisors is an integer number (662800806229).
Almost surely, 21325601612457 is an apocalyptic number.
It is an amenable number.
1325601612457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325601612457 is an equidigital number, since it uses as much as digits as its factorization.
1325601612457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
Adding to 1325601612457 its reverse (7542161065231), we get a palindrome (8867762677688).
The spelling of 1325601612457 in words is "one trillion, three hundred twenty-five billion, six hundred one million, six hundred twelve thousand, four hundred fifty-seven".
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