Base | Representation |
---|---|
bin | 11000101100010010… |
… | …10010000111010001 |
3 | 1021012212022121221211 |
4 | 30112021102013101 |
5 | 204122121343004 |
6 | 10031231220121 |
7 | 646335555001 |
oct | 142611220721 |
9 | 37185277854 |
10 | 13256434129 |
11 | 5692a03194 |
12 | 269b677641 |
13 | 1333557b83 |
14 | 8da83c001 |
15 | 528c07504 |
hex | 3162521d1 |
13256434129 has 2 divisors, whose sum is σ = 13256434130. Its totient is φ = 13256434128.
The previous prime is 13256434099. The next prime is 13256434133. The reversal of 13256434129 is 92143465231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13219710529 + 36723600 = 114977^2 + 6060^2 .
It is a cyclic number.
It is not a de Polignac number, because 13256434129 - 27 = 13256434001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13256434091 and 13256434100.
It is not a weakly prime, because it can be changed into another prime (13256434189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6628217064 + 6628217065.
It is an arithmetic number, because the mean of its divisors is an integer number (6628217065).
Almost surely, 213256434129 is an apocalyptic number.
It is an amenable number.
13256434129 is a deficient number, since it is larger than the sum of its proper divisors (1).
13256434129 is an equidigital number, since it uses as much as digits as its factorization.
13256434129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 40.
The spelling of 13256434129 in words is "thirteen billion, two hundred fifty-six million, four hundred thirty-four thousand, one hundred twenty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •