Base | Representation |
---|---|
bin | 11000101100110010… |
… | …11010011100001001 |
3 | 1021020011021110020112 |
4 | 30112121122130021 |
5 | 204124212200122 |
6 | 10031502004105 |
7 | 646416525503 |
oct | 142631323411 |
9 | 37204243215 |
10 | 13260662537 |
11 | 5695331041 |
12 | 26a0b76635 |
13 | 13343a86a5 |
14 | 8db21cd73 |
15 | 5292902e2 |
hex | 31665a709 |
13260662537 has 2 divisors, whose sum is σ = 13260662538. Its totient is φ = 13260662536.
The previous prime is 13260662521. The next prime is 13260662563. The reversal of 13260662537 is 73526606231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10522861561 + 2737800976 = 102581^2 + 52324^2 .
It is a cyclic number.
It is not a de Polignac number, because 13260662537 - 24 = 13260662521 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13260662494 and 13260662503.
It is not a weakly prime, because it can be changed into another prime (13260632537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6630331268 + 6630331269.
It is an arithmetic number, because the mean of its divisors is an integer number (6630331269).
Almost surely, 213260662537 is an apocalyptic number.
It is an amenable number.
13260662537 is a deficient number, since it is larger than the sum of its proper divisors (1).
13260662537 is an equidigital number, since it uses as much as digits as its factorization.
13260662537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 41.
The spelling of 13260662537 in words is "thirteen billion, two hundred sixty million, six hundred sixty-two thousand, five hundred thirty-seven".
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