Base | Representation |
---|---|
bin | 1100000011111010010010… |
… | …0001111100001000000011 |
3 | 1201221202210111110200011121 |
4 | 3000332210201330020003 |
5 | 3214233143021400303 |
6 | 44112100205253111 |
7 | 2536045660362052 |
oct | 300764441741003 |
9 | 51852714420147 |
10 | 13261324403203 |
11 | 42531069a3758 |
12 | 15a2172864197 |
13 | 7526cac350b6 |
14 | 33bbcc830399 |
15 | 17ee5676e9bd |
hex | c0fa487c203 |
13261324403203 has 4 divisors (see below), whose sum is σ = 13261331687200. Its totient is φ = 13261317119208.
The previous prime is 13261324403153. The next prime is 13261324403219. The reversal of 13261324403203 is 30230442316231.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13261324403203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13261324403603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1741273 + ... + 5436421.
It is an arithmetic number, because the mean of its divisors is an integer number (3315332921800).
Almost surely, 213261324403203 is an apocalyptic number.
13261324403203 is a deficient number, since it is larger than the sum of its proper divisors (7283997).
13261324403203 is an equidigital number, since it uses as much as digits as its factorization.
13261324403203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7283996.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 13261324403203 its reverse (30230442316231), we get a palindrome (43491766719434).
The spelling of 13261324403203 in words is "thirteen trillion, two hundred sixty-one billion, three hundred twenty-four million, four hundred three thousand, two hundred three".
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