Base | Representation |
---|---|
bin | 11110001010010111001101… |
… | …100001110101000110111011 |
3 | 122101200112220102010002102102 |
4 | 132022113031201311012323 |
5 | 114341343343330301043 |
6 | 1150044103241254015 |
7 | 36640620501203153 |
oct | 3612271541650673 |
9 | 571615812102372 |
10 | 132653513134523 |
11 | 392a4047992617 |
12 | 12a6518119430b |
13 | 59032323015a4 |
14 | 24a867003d763 |
15 | 10509503dc6b8 |
hex | 78a5cd8751bb |
132653513134523 has 2 divisors, whose sum is σ = 132653513134524. Its totient is φ = 132653513134522.
The previous prime is 132653513134511. The next prime is 132653513134543. The reversal of 132653513134523 is 325431315356231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132653513134523 - 218 = 132653512872379 is a prime.
It is not a weakly prime, because it can be changed into another prime (132653513134543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326756567261 + 66326756567262.
It is an arithmetic number, because the mean of its divisors is an integer number (66326756567262).
Almost surely, 2132653513134523 is an apocalyptic number.
132653513134523 is a deficient number, since it is larger than the sum of its proper divisors (1).
132653513134523 is an equidigital number, since it uses as much as digits as its factorization.
132653513134523 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2916000, while the sum is 47.
The spelling of 132653513134523 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred thirteen million, one hundred thirty-four thousand, five hundred twenty-three".
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