Search a number
-
+
13265566503401 = 54493243436157
BaseRepresentation
bin1100000100001010000101…
…1000010001000111101001
31201222011202010201200122202
43001002201120101013221
53214320340011102101
644114041144225545
72536256050546112
oct301024130210751
951864663650582
1013265566503401
114254993505393
1215a2b5746b2b5
13752c25a61564
1433c0b1da5209
15180103db836b
hexc10a16111e9

13265566503401 has 4 divisors (see below), whose sum is σ = 13265809994052. Its totient is φ = 13265323012752.

The previous prime is 13265566503257. The next prime is 13265566503419. The reversal of 13265566503401 is 10430566556231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5779191960025 + 7486374543376 = 2403995^2 + 2736124^2 .

It is a cyclic number.

It is not a de Polignac number, because 13265566503401 - 242 = 8867519992297 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13265566503421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121663586 + ... + 121772571.

It is an arithmetic number, because the mean of its divisors is an integer number (3316452498513).

Almost surely, 213265566503401 is an apocalyptic number.

It is an amenable number.

13265566503401 is a deficient number, since it is larger than the sum of its proper divisors (243490651).

13265566503401 is an equidigital number, since it uses as much as digits as its factorization.

13265566503401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243490650.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 13265566503401 in words is "thirteen trillion, two hundred sixty-five billion, five hundred sixty-six million, five hundred three thousand, four hundred one".

Divisors: 1 54493 243436157 13265566503401