Base | Representation |
---|---|
bin | 11110001010011001101001… |
… | …110111111000111110001011 |
3 | 122101200210200012210202100002 |
4 | 132022121221313320332023 |
5 | 114341414231324210321 |
6 | 1150045215422033215 |
7 | 36641042501446133 |
oct | 3612315167707613 |
9 | 571623605722302 |
10 | 132656136163211 |
11 | 392a5173586921 |
12 | 12a6579371880b |
13 | 590355c87837b |
14 | 24a883c557ac3 |
15 | 1050a5581b20b |
hex | 78a669df8f8b |
132656136163211 has 4 divisors (see below), whose sum is σ = 133389042993024. Its totient is φ = 131923229333400.
The previous prime is 132656136163189. The next prime is 132656136163231. The reversal of 132656136163211 is 112361631656231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132656136163211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132656136163231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366453414635 + ... + 366453414996.
It is an arithmetic number, because the mean of its divisors is an integer number (33347260748256).
Almost surely, 2132656136163211 is an apocalyptic number.
132656136163211 is a deficient number, since it is larger than the sum of its proper divisors (732906829813).
132656136163211 is an equidigital number, since it uses as much as digits as its factorization.
132656136163211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 732906829812.
The product of its digits is 699840, while the sum is 47.
The spelling of 132656136163211 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, one hundred thirty-six million, one hundred sixty-three thousand, two hundred eleven".
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