Base | Representation |
---|---|
bin | 11110001010011001101010… |
… | …101110001111010000000001 |
3 | 122101200210201012121120120212 |
4 | 132022121222232033100001 |
5 | 114341414244001111431 |
6 | 1150045221051243505 |
7 | 36641043033524513 |
oct | 3612315256172001 |
9 | 571623635546525 |
10 | 132656150410241 |
11 | 392a5180627927 |
12 | 12a65798449595 |
13 | 59035627c6073 |
14 | 24a88403c5bb3 |
15 | 1050a56bd272b |
hex | 78a66ab8f401 |
132656150410241 has 2 divisors, whose sum is σ = 132656150410242. Its totient is φ = 132656150410240.
The previous prime is 132656150410237. The next prime is 132656150410283. The reversal of 132656150410241 is 142014051656231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113100651344641 + 19555499065600 = 10634879^2 + 4422160^2 .
It is a cyclic number.
It is not a de Polignac number, because 132656150410241 - 22 = 132656150410237 is a prime.
It is not a weakly prime, because it can be changed into another prime (132656170410241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328075205120 + 66328075205121.
It is an arithmetic number, because the mean of its divisors is an integer number (66328075205121).
Almost surely, 2132656150410241 is an apocalyptic number.
It is an amenable number.
132656150410241 is a deficient number, since it is larger than the sum of its proper divisors (1).
132656150410241 is an equidigital number, since it uses as much as digits as its factorization.
132656150410241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 132656150410241 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, one hundred fifty million, four hundred ten thousand, two hundred forty-one".
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