Base | Representation |
---|---|
bin | 11110001010011001110100… |
… | …110101111011110111011011 |
3 | 122101200211011001002210120012 |
4 | 132022121310311323313123 |
5 | 114341420120432401110 |
6 | 1150045245554352135 |
7 | 36641050164650033 |
oct | 3612316465736733 |
9 | 571624131083505 |
10 | 132656320200155 |
11 | 392a5258456574 |
12 | 12a6582528b64b |
13 | 590358ba3387b |
14 | 24a8858b828c3 |
15 | 1050a66a70905 |
hex | 78a674d7bddb |
132656320200155 has 32 divisors (see below), whose sum is σ = 160290416351808. Its totient is φ = 105392506060800.
The previous prime is 132656320200137. The next prime is 132656320200191. The reversal of 132656320200155 is 551002023656231.
It is not a de Polignac number, because 132656320200155 - 214 = 132656320183771 is a prime.
It is a super-3 number, since 3×1326563202001553 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2424203195 + ... + 2424257915.
It is an arithmetic number, because the mean of its divisors is an integer number (5009075510994).
Almost surely, 2132656320200155 is an apocalyptic number.
132656320200155 is a deficient number, since it is larger than the sum of its proper divisors (27634096151653).
132656320200155 is a wasteful number, since it uses less digits than its factorization.
132656320200155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60767.
The product of its (nonzero) digits is 324000, while the sum is 41.
Adding to 132656320200155 its reverse (551002023656231), we get a palindrome (683658343856386).
The spelling of 132656320200155 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred twenty million, two hundred thousand, one hundred fifty-five".
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