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132656343241433 = 1156384011254971
BaseRepresentation
bin11110001010011001110110…
…001101110101001011011001
3122101200211012122110102020212
4132022121312031311023121
5114341420142332211213
61150045252140300505
736641050564543544
oct3612316615651331
9571624178412225
10132656343241433
11392a526a463850
1212a65830b41735
13590359374036b
1424a885bc5d85b
151050a68ac29a8
hex78a6763752d9

132656343241433 has 16 divisors (see below), whose sum is σ = 144975349469952. Its totient is φ = 120380566914000.

The previous prime is 132656343241417. The next prime is 132656343241447. The reversal of 132656343241433 is 334142343656231.

It is a cyclic number.

It is not a de Polignac number, because 132656343241433 - 24 = 132656343241417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132656343241453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 520152638 + ... + 520407608.

It is an arithmetic number, because the mean of its divisors is an integer number (9060959341872).

Almost surely, 2132656343241433 is an apocalyptic number.

It is an amenable number.

132656343241433 is a deficient number, since it is larger than the sum of its proper divisors (12319006228519).

132656343241433 is a wasteful number, since it uses less digits than its factorization.

132656343241433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339556.

The product of its digits is 11197440, while the sum is 50.

Adding to 132656343241433 its reverse (334142343656231), we get a palindrome (466798686897664).

The spelling of 132656343241433 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred forty-three million, two hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 11 563 6193 84011 254971 924121 2804681 47298193 143548673 520280123 1579035403 21420368681 235624055491 12059667567403 132656343241433