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13265644253353 is a prime number
BaseRepresentation
bin1100000100001010011000…
…0000110111000010101001
31201222011221120000210112121
43001002212000313002221
53214321014412101403
644114053002511241
72536261013451262
oct301024600670251
951864846023477
1013265644253353
114254a2338a048
1215a2b79505521
13752c38bb474b
1433c0bc443969
1518010ab253bd
hexc10a60370a9

13265644253353 has 2 divisors, whose sum is σ = 13265644253354. Its totient is φ = 13265644253352.

The previous prime is 13265644253321. The next prime is 13265644253423. The reversal of 13265644253353 is 35335244656231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12921494243904 + 344150009449 = 3594648^2 + 586643^2 .

It is a cyclic number.

It is not a de Polignac number, because 13265644253353 - 25 = 13265644253321 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13265644253353.

It is not a weakly prime, because it can be changed into another prime (13265644254353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6632822126676 + 6632822126677.

It is an arithmetic number, because the mean of its divisors is an integer number (6632822126677).

Almost surely, 213265644253353 is an apocalyptic number.

It is an amenable number.

13265644253353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13265644253353 is an equidigital number, since it uses as much as digits as its factorization.

13265644253353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 23328000, while the sum is 52.

The spelling of 13265644253353 in words is "thirteen trillion, two hundred sixty-five billion, six hundred forty-four million, two hundred fifty-three thousand, three hundred fifty-three".