Base | Representation |
---|---|
bin | 1100000100001010110110… |
… | …0001000010111001101010 |
3 | 1201222012021022220001021112 |
4 | 3001002231201002321222 |
5 | 3214321244123143200 |
6 | 44114113300510322 |
7 | 2536264102422533 |
oct | 301025541027152 |
9 | 51865238801245 |
10 | 13265770131050 |
11 | 4254a884458a8 |
12 | 15a2bb36ab3a2 |
13 | 752c58cb8aa8 |
14 | 33c0d104d68a |
15 | 180116bdc535 |
hex | c10ad842e6a |
13265770131050 has 192 divisors, whose sum is σ = 26878838394240. Its totient is φ = 4854334464000.
The previous prime is 13265770131017. The next prime is 13265770131077. The reversal of 13265770131050 is 5013107756231.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a junction number, because it is equal to n+sod(n) for n = 13265770130989 and 13265770131007.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4141668749 + ... + 4141671951.
It is an arithmetic number, because the mean of its divisors is an integer number (139993949970).
Almost surely, 213265770131050 is an apocalyptic number.
13265770131050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13265770131050 is an abundant number, since it is smaller than the sum of its proper divisors (13613068263190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13265770131050 is a wasteful number, since it uses less digits than its factorization.
13265770131050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4329 (or 4324 counting only the distinct ones).
The product of its (nonzero) digits is 132300, while the sum is 41.
Adding to 13265770131050 its reverse (5013107756231), we get a palindrome (18278877887281).
The spelling of 13265770131050 in words is "thirteen trillion, two hundred sixty-five billion, seven hundred seventy million, one hundred thirty-one thousand, fifty".
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