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13265770131050 = 25219411139413203
BaseRepresentation
bin1100000100001010110110…
…0001000010111001101010
31201222012021022220001021112
43001002231201002321222
53214321244123143200
644114113300510322
72536264102422533
oct301025541027152
951865238801245
1013265770131050
114254a884458a8
1215a2bb36ab3a2
13752c58cb8aa8
1433c0d104d68a
15180116bdc535
hexc10ad842e6a

13265770131050 has 192 divisors, whose sum is σ = 26878838394240. Its totient is φ = 4854334464000.

The previous prime is 13265770131017. The next prime is 13265770131077. The reversal of 13265770131050 is 5013107756231.

It is a Harshad number since it is a multiple of its sum of digits (41).

It is a junction number, because it is equal to n+sod(n) for n = 13265770130989 and 13265770131007.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4141668749 + ... + 4141671951.

It is an arithmetic number, because the mean of its divisors is an integer number (139993949970).

Almost surely, 213265770131050 is an apocalyptic number.

13265770131050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13265770131050 is an abundant number, since it is smaller than the sum of its proper divisors (13613068263190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13265770131050 is a wasteful number, since it uses less digits than its factorization.

13265770131050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4329 (or 4324 counting only the distinct ones).

The product of its (nonzero) digits is 132300, while the sum is 41.

Adding to 13265770131050 its reverse (5013107756231), we get a palindrome (18278877887281).

The spelling of 13265770131050 in words is "thirteen trillion, two hundred sixty-five billion, seven hundred seventy million, one hundred thirty-one thousand, fifty".