Base | Representation |
---|---|
bin | 1100000100010101111100… |
… | …1101000111001010100011 |
3 | 1201222110222002101120210120 |
4 | 3001011133031013022203 |
5 | 3214343400310000313 |
6 | 44115325152331323 |
7 | 2536431011466630 |
oct | 301053715071243 |
9 | 51873862346716 |
10 | 13268751250083 |
11 | 425627818a73a |
12 | 15a36a5b43b43 |
13 | 7533127bc354 |
14 | 33c2d4d3d187 |
15 | 18023d7a1d23 |
hex | c115f3472a3 |
13268751250083 has 16 divisors (see below), whose sum is σ = 20220126007296. Its totient is φ = 7581739890240.
The previous prime is 13268751250067. The next prime is 13268751250099. The reversal of 13268751250083 is 38005215786231.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (13268751250067) and next prime (13268751250099).
It is not a de Polignac number, because 13268751250083 - 24 = 13268751250067 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13268701250083) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16416003 + ... + 17205308.
It is an arithmetic number, because the mean of its divisors is an integer number (1263757875456).
Almost surely, 213268751250083 is an apocalyptic number.
13268751250083 is a deficient number, since it is larger than the sum of its proper divisors (6951374757213).
13268751250083 is a wasteful number, since it uses less digits than its factorization.
13268751250083 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33640114.
The product of its (nonzero) digits is 2419200, while the sum is 51.
The spelling of 13268751250083 in words is "thirteen trillion, two hundred sixty-eight billion, seven hundred fifty-one million, two hundred fifty thousand, eighty-three".
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