Base | Representation |
---|---|
bin | 11000101110101111… |
… | …01101010000001011 |
3 | 1021021022000002202211 |
4 | 30113113231100023 |
5 | 204142402230043 |
6 | 10033244005551 |
7 | 650005401004 |
oct | 142727552013 |
9 | 37238002684 |
10 | 13276992523 |
11 | 56a3574aa3 |
12 | 26a65308b7 |
13 | 13378a54c2 |
14 | 8dd4701ab |
15 | 52a918a9d |
hex | 3175ed40b |
13276992523 has 2 divisors, whose sum is σ = 13276992524. Its totient is φ = 13276992522.
The previous prime is 13276992493. The next prime is 13276992583. The reversal of 13276992523 is 32529967231.
It is a weak prime.
It is an emirp because it is prime and its reverse (32529967231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13276992523 - 29 = 13276992011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13276992583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6638496261 + 6638496262.
It is an arithmetic number, because the mean of its divisors is an integer number (6638496262).
Almost surely, 213276992523 is an apocalyptic number.
13276992523 is a deficient number, since it is larger than the sum of its proper divisors (1).
13276992523 is an equidigital number, since it uses as much as digits as its factorization.
13276992523 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1224720, while the sum is 49.
The spelling of 13276992523 in words is "thirteen billion, two hundred seventy-six million, nine hundred ninety-two thousand, five hundred twenty-three".
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