Base | Representation |
---|---|
bin | 111101110100111001… |
… | …0101101110111111011 |
3 | 110200201001211012222211 |
4 | 1323221302231313323 |
5 | 4133403434432212 |
6 | 140554435555551 |
7 | 12410125216132 |
oct | 1735162556773 |
9 | 420631735884 |
10 | 132771405307 |
11 | 51342aa6a42 |
12 | 21894a5bbb7 |
13 | c69c0cc628 |
14 | 65d75a8919 |
15 | 36c13009a7 |
hex | 1ee9caddfb |
132771405307 has 2 divisors, whose sum is σ = 132771405308. Its totient is φ = 132771405306.
The previous prime is 132771405253. The next prime is 132771405419. The reversal of 132771405307 is 703504177231.
It is a weak prime.
It is an emirp because it is prime and its reverse (703504177231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132771405307 - 235 = 98411666939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132771405307.
It is not a weakly prime, because it can be changed into another prime (132771405007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66385702653 + 66385702654.
It is an arithmetic number, because the mean of its divisors is an integer number (66385702654).
Almost surely, 2132771405307 is an apocalyptic number.
132771405307 is a deficient number, since it is larger than the sum of its proper divisors (1).
132771405307 is an equidigital number, since it uses as much as digits as its factorization.
132771405307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 123480, while the sum is 40.
The spelling of 132771405307 in words is "one hundred thirty-two billion, seven hundred seventy-one million, four hundred five thousand, three hundred seven".
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