Base | Representation |
---|---|
bin | 1100000101001011100010… |
… | …1011000000111111001001 |
3 | 1202000212002200000200122211 |
4 | 3001102320223000333021 |
5 | 3220112331103210314 |
6 | 44130104452345121 |
7 | 2540450343646414 |
oct | 301227053007711 |
9 | 52025080020584 |
10 | 13283137163209 |
11 | 426138a702141 |
12 | 15a643b9151a1 |
13 | 754796049994 |
14 | 33cc9b790b7b |
15 | 1807d17149c4 |
hex | c14b8ac0fc9 |
13283137163209 has 2 divisors, whose sum is σ = 13283137163210. Its totient is φ = 13283137163208.
The previous prime is 13283137163173. The next prime is 13283137163267. The reversal of 13283137163209 is 90236173138231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8833990673209 + 4449146490000 = 2972203^2 + 2109300^2 .
It is a cyclic number.
It is not a de Polignac number, because 13283137163209 - 233 = 13274547228617 is a prime.
It is a super-4 number, since 4×132831371632094 (a number of 54 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (13283137163269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6641568581604 + 6641568581605.
It is an arithmetic number, because the mean of its divisors is an integer number (6641568581605).
Almost surely, 213283137163209 is an apocalyptic number.
It is an amenable number.
13283137163209 is a deficient number, since it is larger than the sum of its proper divisors (1).
13283137163209 is an equidigital number, since it uses as much as digits as its factorization.
13283137163209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 49.
The spelling of 13283137163209 in words is "thirteen trillion, two hundred eighty-three billion, one hundred thirty-seven million, one hundred sixty-three thousand, two hundred nine".
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