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13283780238041 is a prime number
BaseRepresentation
bin1100000101001101111100…
…0000001001101011011001
31202000220202111002021111012
43001103133000021223121
53220120140220104131
644130252343543305
72540502313001225
oct301233700115331
952026674067435
1013283780238041
11426168a700845
1215a659b15ab35
13754869347831
1433cd1cd4b785
1518081cde052b
hexc14df009ad9

13283780238041 has 2 divisors, whose sum is σ = 13283780238042. Its totient is φ = 13283780238040.

The previous prime is 13283780238031. The next prime is 13283780238049. The reversal of 13283780238041 is 14083208738231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9755502624400 + 3528277613641 = 3123380^2 + 1878371^2 .

It is a cyclic number.

It is not a de Polignac number, because 13283780238041 - 26 = 13283780237977 is a prime.

It is not a weakly prime, because it can be changed into another prime (13283780238049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6641890119020 + 6641890119021.

It is an arithmetic number, because the mean of its divisors is an integer number (6641890119021).

Almost surely, 213283780238041 is an apocalyptic number.

It is an amenable number.

13283780238041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13283780238041 is an equidigital number, since it uses as much as digits as its factorization.

13283780238041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1548288, while the sum is 50.

The spelling of 13283780238041 in words is "thirteen trillion, two hundred eighty-three billion, seven hundred eighty million, two hundred thirty-eight thousand, forty-one".