Base | Representation |
---|---|
bin | 1100000101011101110110… |
… | …1100011000000001111011 |
3 | 1202001022210021111110202011 |
4 | 3001113131230120001323 |
5 | 3220202413112302102 |
6 | 44132240345150351 |
7 | 2541013226645512 |
oct | 301273554300173 |
9 | 52038707443664 |
10 | 13288053244027 |
11 | 4263482701451 |
12 | 15a739218b3b7 |
13 | 75509a6a5343 |
14 | 33d206649679 |
15 | 1809bd0e12d7 |
hex | c15ddb1807b |
13288053244027 has 2 divisors, whose sum is σ = 13288053244028. Its totient is φ = 13288053244026.
The previous prime is 13288053243943. The next prime is 13288053244157. The reversal of 13288053244027 is 72044235088231.
13288053244027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13288053244027 - 215 = 13288053211259 is a prime.
It is a super-2 number, since 2×132880532440272 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13288053241027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6644026622013 + 6644026622014.
It is an arithmetic number, because the mean of its divisors is an integer number (6644026622014).
Almost surely, 213288053244027 is an apocalyptic number.
13288053244027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13288053244027 is an equidigital number, since it uses as much as digits as its factorization.
13288053244027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2580480, while the sum is 49.
The spelling of 13288053244027 in words is "thirteen trillion, two hundred eighty-eight billion, fifty-three million, two hundred forty-four thousand, twenty-seven".
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