1330002423043 has 4 divisors (see below), whose sum is σ = 1520002769200. Its totient is φ = 1140002076888.

The previous prime is 1330002423031. The next prime is 1330002423059. The reversal of 1330002423043 is 3403242000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1330002423043 is a prime.

It is a super-2 number, since 2×1330002423043² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330002422999 and 1330002423017.

It is not an unprimeable number, because it can be changed into a prime (1330002423023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95000173068 + ... + 95000173081.

It is an arithmetic number, because the mean of its divisors is an integer number (380000692300).

Almost surely, 2^{1330002423043} is an apocalyptic number.

1330002423043 is a deficient number, since it is larger than the sum of its proper divisors (190000346157).

1330002423043 is an equidigital number, since it uses as much as digits as its factorization.

1330002423043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190000346156.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 1330002423043 its reverse (3403242000331), we get a palindrome (4733244423374).

The spelling of 1330002423043 in words is "one trillion, three hundred thirty billion, two million, four hundred twenty-three thousand, forty-three".