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133000643 is a prime number
BaseRepresentation
bin1111110110101…
…10110111000011
3100021021010120202
413323112313003
5233022010033
621110355415
73203325656
oct773266703
9307233522
10133000643
1169091396
123865bb6b
1321729509
141394189d
15ba228e8
hex7ed6dc3

133000643 has 2 divisors, whose sum is σ = 133000644. Its totient is φ = 133000642.

The previous prime is 133000619. The next prime is 133000657. The reversal of 133000643 is 346000331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133000643 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133000603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500321 + 66500322.

It is an arithmetic number, because the mean of its divisors is an integer number (66500322).

Almost surely, 2133000643 is an apocalyptic number.

133000643 is a deficient number, since it is larger than the sum of its proper divisors (1).

133000643 is an equidigital number, since it uses as much as digits as its factorization.

133000643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 20.

The square root of 133000643 is about 11532.5904722226. The cubic root of 133000643 is about 510.4476947987.

Adding to 133000643 its reverse (346000331), we get a palindrome (479000974).

The spelling of 133000643 in words is "one hundred thirty-three million, six hundred forty-three", and thus it is an aban number.