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133001034410137 is a prime number
BaseRepresentation
bin11110001111011010110111…
…011010010010100010011001
3122102220202220202201001011111
4132033122313122102202121
5114413042104302111022
61150511455352300321
740005002422253545
oct3617326732224231
9572822822631144
10133001034410137
113941847065a613
1212b005a93a16a1
135929c364ac69a
1424bb3da5dca25
1510599dea19477
hex78f6b7692899

133001034410137 has 2 divisors, whose sum is σ = 133001034410138. Its totient is φ = 133001034410136.

The previous prime is 133001034410081. The next prime is 133001034410221. The reversal of 133001034410137 is 731014430100331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79215179884681 + 53785854525456 = 8900291^2 + 7333884^2 .

It is a cyclic number.

It is not a de Polignac number, because 133001034410137 - 27 = 133001034410009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133001034410099 and 133001034410108.

It is not a weakly prime, because it can be changed into another prime (133001034410737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500517205068 + 66500517205069.

It is an arithmetic number, because the mean of its divisors is an integer number (66500517205069).

Almost surely, 2133001034410137 is an apocalyptic number.

It is an amenable number.

133001034410137 is a deficient number, since it is larger than the sum of its proper divisors (1).

133001034410137 is an equidigital number, since it uses as much as digits as its factorization.

133001034410137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

Adding to 133001034410137 its reverse (731014430100331), we get a palindrome (864015464510468).

The spelling of 133001034410137 in words is "one hundred thirty-three trillion, one billion, thirty-four million, four hundred ten thousand, one hundred thirty-seven".