Base | Representation |
---|---|
bin | 1100000110001010110001… |
… | …1001011100110001011011 |
3 | 1202002110220121111001222011 |
4 | 3001202230121130301123 |
5 | 3220402111420213034 |
6 | 44141553043010351 |
7 | 2541621103022521 |
oct | 301425431346133 |
9 | 52073817431864 |
10 | 13300111101019 |
11 | 42685aaa8a916 |
12 | 15a97983699b7 |
13 | 75626c816572 |
14 | 33da2bc08311 |
15 | 180e7698e864 |
hex | c18ac65cc5b |
13300111101019 has 2 divisors, whose sum is σ = 13300111101020. Its totient is φ = 13300111101018.
The previous prime is 13300111100953. The next prime is 13300111101031. The reversal of 13300111101019 is 91010111100331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300111101019 is a prime.
It is a super-2 number, since 2×133001111010192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13300111101619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650055550509 + 6650055550510.
It is an arithmetic number, because the mean of its divisors is an integer number (6650055550510).
Almost surely, 213300111101019 is an apocalyptic number.
13300111101019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300111101019 is an equidigital number, since it uses as much as digits as its factorization.
13300111101019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 22.
The spelling of 13300111101019 in words is "thirteen trillion, three hundred billion, one hundred eleven million, one hundred one thousand, nineteen".
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