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133001113099433 is a prime number
BaseRepresentation
bin11110001111011010111100…
…000110011101110010101001
3122102220210010020202212120212
4132033122330012131302221
5114413042234423140213
61150511511243030505
740005004366150445
oct3617327406356251
9572823106685525
10133001113099433
1139418501015a97
1212b0060b80b435
135929c498a12b7
1424bb406c43825
1510599e68ae9a8
hex78f6bc19dca9

133001113099433 has 2 divisors, whose sum is σ = 133001113099434. Its totient is φ = 133001113099432.

The previous prime is 133001113099391. The next prime is 133001113099471. The reversal of 133001113099433 is 334990311100331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132996180565609 + 4932533824 = 11532397^2 + 70232^2 .

It is a cyclic number.

It is not a de Polignac number, because 133001113099433 - 230 = 133000039357609 is a prime.

It is not a weakly prime, because it can be changed into another prime (133001113099493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500556549716 + 66500556549717.

It is an arithmetic number, because the mean of its divisors is an integer number (66500556549717).

Almost surely, 2133001113099433 is an apocalyptic number.

It is an amenable number.

133001113099433 is a deficient number, since it is larger than the sum of its proper divisors (1).

133001113099433 is an equidigital number, since it uses as much as digits as its factorization.

133001113099433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78732, while the sum is 41.

Adding to 133001113099433 its reverse (334990311100331), we get a palindrome (467991424199764).

The spelling of 133001113099433 in words is "one hundred thirty-three trillion, one billion, one hundred thirteen million, ninety-nine thousand, four hundred thirty-three".