1330011232041 has 4 divisors (see below), whose sum is σ = 1773348309392. Its totient is φ = 886674154692.

The previous prime is 1330011231977. The next prime is 1330011232111. The reversal of 1330011232041 is 1402321100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1330011232041 - 2⁶ = 1330011231977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330011231999 and 1330011232017.

It is not an unprimeable number, because it can be changed into a prime (1330011232241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221668538671 + ... + 221668538676.

It is an arithmetic number, because the mean of its divisors is an integer number (443337077348).

Almost surely, 2^{1330011232041} is an apocalyptic number.

It is an amenable number.

1330011232041 is a deficient number, since it is larger than the sum of its proper divisors (443337077351).

1330011232041 is an equidigital number, since it uses as much as digits as its factorization.

1330011232041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 443337077350.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1330011232041 its reverse (1402321100331), we get a palindrome (2732332332372).

The spelling of 1330011232041 in words is "one trillion, three hundred thirty billion, eleven million, two hundred thirty-two thousand, forty-one".