133001222222113 has 4 divisors (see below), whose sum is σ = 152001396825280. Its totient is φ = 114001047618948.

The previous prime is 133001222222041. The next prime is 133001222222119. The reversal of 133001222222113 is 311222222100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 133001222222113 - 2¹³ = 133001222213921 is a prime.

It is a super-2 number, since 2×133001222222113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133001222222119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9500087301573 + ... + 9500087301586.

It is an arithmetic number, because the mean of its divisors is an integer number (38000349206320).

Almost surely, 2^{133001222222113} is an apocalyptic number.

It is an amenable number.

133001222222113 is a deficient number, since it is larger than the sum of its proper divisors (19000174603167).

133001222222113 is an equidigital number, since it uses as much as digits as its factorization.

133001222222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19000174603166.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 133001222222113 its reverse (311222222100331), we get a palindrome (444223444322444).

The spelling of 133001222222113 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-two million, two hundred twenty-two thousand, one hundred thirteen".