Base | Representation |
---|---|
bin | 11110001111011011000010… |
… | …100111000000101000001011 |
3 | 122102220210101212020112102002 |
4 | 132033123002213000220023 |
5 | 114413043000401402102 |
6 | 1150511530143301215 |
7 | 40005010163246153 |
oct | 3617330247005013 |
9 | 572823355215362 |
10 | 133001222294027 |
11 | 3941855771755a |
12 | 12b006402aa80b |
13 | 5929c663b3b99 |
14 | 24bb417549763 |
15 | 1059a0127d902 |
hex | 78f6c29c0a0b |
133001222294027 has 2 divisors, whose sum is σ = 133001222294028. Its totient is φ = 133001222294026.
The previous prime is 133001222294011. The next prime is 133001222294099. The reversal of 133001222294027 is 720492222100331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133001222294027 - 24 = 133001222294011 is a prime.
It is not a weakly prime, because it can be changed into another prime (133001222294827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500611147013 + 66500611147014.
It is an arithmetic number, because the mean of its divisors is an integer number (66500611147014).
Almost surely, 2133001222294027 is an apocalyptic number.
133001222294027 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001222294027 is an equidigital number, since it uses as much as digits as its factorization.
133001222294027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 38.
Adding to 133001222294027 its reverse (720492222100331), we get a palindrome (853493444394358).
The spelling of 133001222294027 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-two million, two hundred ninety-four thousand, twenty-seven".
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