Base | Representation |
---|---|
bin | 11110001111011011001111… |
… | …000111111001001101110011 |
3 | 122102220210221111021221112022 |
4 | 132033123033013321031303 |
5 | 114413043413123203021 |
6 | 1150512003043222055 |
7 | 40005015322622405 |
oct | 3617331707711563 |
9 | 572823844257468 |
10 | 133001432241011 |
11 | 39418655183864 |
12 | 12b0069a67792b |
13 | 5929c9aa41879 |
14 | 24bb43739ab75 |
15 | 1059a149001ab |
hex | 78f6cf1f9373 |
133001432241011 has 4 divisors (see below), whose sum is σ = 133001536096800. Its totient is φ = 133001328385224.
The previous prime is 133001432241001. The next prime is 133001432241031. The reversal of 133001432241011 is 110142234100331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133001432241011 - 26 = 133001432240947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133001432241001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49982651 + ... + 52576308.
It is an arithmetic number, because the mean of its divisors is an integer number (33250384024200).
Almost surely, 2133001432241011 is an apocalyptic number.
133001432241011 is a deficient number, since it is larger than the sum of its proper divisors (103855789).
133001432241011 is a wasteful number, since it uses less digits than its factorization.
133001432241011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103855788.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 133001432241011 its reverse (110142234100331), we get a palindrome (243143666341342).
The spelling of 133001432241011 in words is "one hundred thirty-three trillion, one billion, four hundred thirty-two million, two hundred forty-one thousand, eleven".
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