Base | Representation |
---|---|
bin | 10011010110101011011… |
… | …011110111010110100011 |
3 | 11201011000110100111111021 |
4 | 103112223123313112203 |
5 | 133242340400244021 |
6 | 2455000412030311 |
7 | 165043106562136 |
oct | 23265333672643 |
9 | 4634013314437 |
10 | 1330021103011 |
11 | 47307126a227 |
12 | 195925462397 |
13 | 9856096aa13 |
14 | 4853272821d |
15 | 248e481bc41 |
hex | 135ab6f75a3 |
1330021103011 has 4 divisors (see below), whose sum is σ = 1343732660872. Its totient is φ = 1316309545152.
The previous prime is 1330021102967. The next prime is 1330021103023. The reversal of 1330021103011 is 1103011200331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330021103011 - 219 = 1330020578723 is a prime.
It is a super-2 number, since 2×13300211030112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1330021103051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6855778785 + ... + 6855778978.
It is an arithmetic number, because the mean of its divisors is an integer number (335933165218).
Almost surely, 21330021103011 is an apocalyptic number.
1330021103011 is a deficient number, since it is larger than the sum of its proper divisors (13711557861).
1330021103011 is an equidigital number, since it uses as much as digits as its factorization.
1330021103011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13711557860.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1330021103011 its reverse (1103011200331), we get a palindrome (2433032303342).
The spelling of 1330021103011 in words is "one trillion, three hundred thirty billion, twenty-one million, one hundred three thousand, eleven".
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