Base | Representation |
---|---|
bin | 11110001111011011111000… |
… | …001100111101001111111111 |
3 | 122102220212201112010120201200 |
4 | 132033123320030331033333 |
5 | 114413101321041342421 |
6 | 1150512155303110543 |
7 | 40005041361643626 |
oct | 3617337014751777 |
9 | 572825645116650 |
10 | 133002121434111 |
11 | 39418979211836 |
12 | 12b00851442453 |
13 | 592a07a769037 |
14 | 24bb4a0b206bd |
15 | 1059a5518a726 |
hex | 78f6f833d3ff |
133002121434111 has 48 divisors (see below), whose sum is σ = 192784355094240. Its totient is φ = 88359387217920.
The previous prime is 133002121434107. The next prime is 133002121434163. The reversal of 133002121434111 is 111434121200331.
133002121434111 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 0 + 212 + 1 + 434 + 1 + 11 = 666.
It is not a de Polignac number, because 133002121434111 - 22 = 133002121434107 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133002121436111) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13827016860 + ... + 13827026478.
It is an arithmetic number, because the mean of its divisors is an integer number (4016340731130).
Almost surely, 2133002121434111 is an apocalyptic number.
133002121434111 is a deficient number, since it is larger than the sum of its proper divisors (59782233660129).
133002121434111 is a wasteful number, since it uses less digits than its factorization.
133002121434111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14456 (or 14453 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 133002121434111 its reverse (111434121200331), we get a palindrome (244436242634442).
The spelling of 133002121434111 in words is "one hundred thirty-three trillion, two billion, one hundred twenty-one million, four hundred thirty-four thousand, one hundred eleven".
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