13300213111033 has 2 divisors, whose sum is σ = 13300213111034. Its totient is φ = 13300213111032.

The previous prime is 13300213111013. The next prime is 13300213111043. The reversal of 13300213111033 is 33011131200331.

13300213111033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13030677698809 + 269535412224 = 3609803^2 + 519168^2 .

It is an emirp because it is prime and its reverse (33011131200331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13300213111033 - 2⁵ = 13300213111001 is a prime.

It is a super-2 number, since 2×13300213111033² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13300213110995 and 13300213111013.

It is not a weakly prime, because it can be changed into another prime (13300213111013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650106555516 + 6650106555517.

It is an arithmetic number, because the mean of its divisors is an integer number (6650106555517).

Almost surely, 2^{13300213111033} is an apocalyptic number.

It is an amenable number.

13300213111033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300213111033 is an equidigital number, since it uses as much as digits as its factorization.

13300213111033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13300213111033 its reverse (33011131200331), we get a palindrome (46311344311364).

The spelling of 13300213111033 in words is "thirteen trillion, three hundred billion, two hundred thirteen million, one hundred eleven thousand, thirty-three".