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13300221314 = 26650110657
BaseRepresentation
bin11000110001100000…
…10100010110000010
31021022220201020200102
430120300110112002
5204214324040224
610035433522402
7650410005302
oct143060242602
937286636612
1013300221314
1157056a0146
1226b2273402
13133c649453
14902599602
1552c9a64ae
hex318c14582

13300221314 has 4 divisors (see below), whose sum is σ = 19950331974. Its totient is φ = 6650110656.

The previous prime is 13300221299. The next prime is 13300221329. The reversal of 13300221314 is 41312200331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41312200331 = 402110274111.

It is an interprime number because it is at equal distance from previous prime (13300221299) and next prime (13300221329).

It can be written as a sum of positive squares in only one way, i.e., 10738140625 + 2562080689 = 103625^2 + 50617^2 .

It is a super-3 number, since 3×133002213143 (a number of 31 digits) contains 333 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325055327 + ... + 3325055330.

Almost surely, 213300221314 is an apocalyptic number.

13300221314 is a deficient number, since it is larger than the sum of its proper divisors (6650110660).

13300221314 is an equidigital number, since it uses as much as digits as its factorization.

13300221314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6650110659.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13300221314 its reverse (41312200331), we get a palindrome (54612421645).

The spelling of 13300221314 in words is "thirteen billion, three hundred million, two hundred twenty-one thousand, three hundred fourteen".

Divisors: 1 2 6650110657 13300221314