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13300233113 = 90971146203
BaseRepresentation
bin11000110001100000…
…10111001110011001
31021022220201211212102
430120300113032121
5204214324424423
610035434053145
7650410054556
oct143060271631
937286654772
1013300233113
1157056a8aa2
1226b227a1b5
13133c65192b
1490259da2d
1552c9a9c28
hex318c17399

13300233113 has 4 divisors (see below), whose sum is σ = 13300470288. Its totient is φ = 13299995940.

The previous prime is 13300233097. The next prime is 13300233119. The reversal of 13300233113 is 31133200331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133200331 = 177911749941.

It is a cyclic number.

It is not a de Polignac number, because 13300233113 - 24 = 13300233097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300233119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17870 + ... + 164072.

It is an arithmetic number, because the mean of its divisors is an integer number (3325117572).

Almost surely, 213300233113 is an apocalyptic number.

It is an amenable number.

13300233113 is a deficient number, since it is larger than the sum of its proper divisors (237175).

13300233113 is an equidigital number, since it uses as much as digits as its factorization.

13300233113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237174.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 13300233113 its reverse (31133200331), we get a palindrome (44433433444).

The spelling of 13300233113 in words is "thirteen billion, three hundred million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 90971 146203 13300233113