Base | Representation |
---|---|
bin | 11110001111011100001010… |
… | …001000000001110101000011 |
3 | 122102220220111110221121201211 |
4 | 132033130022020001311003 |
5 | 114413102430031211120 |
6 | 1150512245204110551 |
7 | 40005052002561151 |
oct | 3617341210016503 |
9 | 572826443847654 |
10 | 133002422132035 |
11 | 39419012a22615 |
12 | 12b00916095457 |
13 | 592a0c7b4c6c1 |
14 | 24bb4cca363d1 |
15 | 1059a7178625a |
hex | 78f70a201d43 |
133002422132035 has 16 divisors (see below), whose sum is σ = 162219848104512. Its totient is φ = 104657320771200.
The previous prime is 133002422132017. The next prime is 133002422132117. The reversal of 133002422132035 is 530231224200331.
It is not a de Polignac number, because 133002422132035 - 27 = 133002422131907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133002422131988 and 133002422132006.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165712117 + ... + 166512793.
It is an arithmetic number, because the mean of its divisors is an integer number (10138740506532).
Almost surely, 2133002422132035 is an apocalyptic number.
133002422132035 is a deficient number, since it is larger than the sum of its proper divisors (29217425972477).
133002422132035 is an equidigital number, since it uses as much as digits as its factorization.
133002422132035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1345374.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 133002422132035 its reverse (530231224200331), we get a palindrome (663233646332366).
The spelling of 133002422132035 in words is "one hundred thirty-three trillion, two billion, four hundred twenty-two million, one hundred thirty-two thousand, thirty-five".
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