Base | Representation |
---|---|
bin | 1100000110001011011110… |
… | …1010100010101100101001 |
3 | 1202002111101210011210111202 |
4 | 3001202313222202230221 |
5 | 3220403003313143423 |
6 | 44142023514333545 |
7 | 2541625556530622 |
oct | 301426752425451 |
9 | 52074353153452 |
10 | 13300300131113 |
11 | 426869775aa36 |
12 | 15a982b72a2b5 |
13 | 75629ca2c6a8 |
14 | 33da48d72a49 |
15 | 180e8837d728 |
hex | c18b7aa2b29 |
13300300131113 has 2 divisors, whose sum is σ = 13300300131114. Its totient is φ = 13300300131112.
The previous prime is 13300300131073. The next prime is 13300300131127. The reversal of 13300300131113 is 31113100300331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13012158774169 + 288141356944 = 3607237^2 + 536788^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300300131113 - 236 = 13231580654377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300300101113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650150065556 + 6650150065557.
It is an arithmetic number, because the mean of its divisors is an integer number (6650150065557).
Almost surely, 213300300131113 is an apocalyptic number.
It is an amenable number.
13300300131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300300131113 is an equidigital number, since it uses as much as digits as its factorization.
13300300131113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 13300300131113 its reverse (31113100300331), we get a palindrome (44413400431444).
The spelling of 13300300131113 in words is "thirteen trillion, three hundred billion, three hundred million, one hundred thirty-one thousand, one hundred thirteen".
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