Base | Representation |
---|---|
bin | 1100000110001011011110… |
… | …1011010011110000001011 |
3 | 1202002111101210120000010121 |
4 | 3001202313223103300023 |
5 | 3220403003341111133 |
6 | 44142023522524111 |
7 | 2541625561325464 |
oct | 301426753236013 |
9 | 52074353500117 |
10 | 13300300332043 |
11 | 426869788799a |
12 | 15a982b806637 |
13 | 75629ca9cc9a |
14 | 33da48dc5d6b |
15 | 180e883bd02d |
hex | c18b7ad3c0b |
13300300332043 has 2 divisors, whose sum is σ = 13300300332044. Its totient is φ = 13300300332042.
The previous prime is 13300300331957. The next prime is 13300300332047. The reversal of 13300300332043 is 34023300300331.
13300300332043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300300332043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13300300331999 and 13300300332017.
It is not a weakly prime, because it can be changed into another prime (13300300332047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650150166021 + 6650150166022.
It is an arithmetic number, because the mean of its divisors is an integer number (6650150166022).
Almost surely, 213300300332043 is an apocalyptic number.
13300300332043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300300332043 is an equidigital number, since it uses as much as digits as its factorization.
13300300332043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 25.
Adding to 13300300332043 its reverse (34023300300331), we get a palindrome (47323600632374).
The spelling of 13300300332043 in words is "thirteen trillion, three hundred billion, three hundred million, three hundred thirty-two thousand, forty-three".
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