1330032440041 has 4 divisors (see below), whose sum is σ = 1330037126784. Its totient is φ = 1330027753300.

The previous prime is 1330032440021. The next prime is 1330032440057. The reversal of 1330032440041 is 1400442300331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330032440041 - 2²¹ = 1330030342889 is a prime.

It is a super-2 number, since 2×1330032440041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330032439988 and 1330032440015.

It is not an unprimeable number, because it can be changed into a prime (1330032440021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888225 + ... + 2495086.

It is an arithmetic number, because the mean of its divisors is an integer number (332509281696).

Almost surely, 2^{1330032440041} is an apocalyptic number.

It is an amenable number.

1330032440041 is a deficient number, since it is larger than the sum of its proper divisors (4686743).

1330032440041 is an equidigital number, since it uses as much as digits as its factorization.

1330032440041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4686742.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 1330032440041 its reverse (1400442300331), we get a palindrome (2730474740372).

The spelling of 1330032440041 in words is "one trillion, three hundred thirty billion, thirty-two million, four hundred forty thousand, forty-one".