13300340231401 has 4 divisors (see below), whose sum is σ = 13729383464704. Its totient is φ = 12871296998100.

The previous prime is 13300340231393. The next prime is 13300340231473. The reversal of 13300340231401 is 10413204300331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13300340231401 - 2³ = 13300340231393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300340238401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214521616605 + ... + 214521616666.

It is an arithmetic number, because the mean of its divisors is an integer number (3432345866176).

Almost surely, 2^{13300340231401} is an apocalyptic number.

It is an amenable number.

13300340231401 is a deficient number, since it is larger than the sum of its proper divisors (429043233303).

13300340231401 is an equidigital number, since it uses as much as digits as its factorization.

13300340231401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 429043233302.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13300340231401 its reverse (10413204300331), we get a palindrome (23713544531732).

The spelling of 13300340231401 in words is "thirteen trillion, three hundred billion, three hundred forty million, two hundred thirty-one thousand, four hundred one".