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13300402210441 is a prime number
BaseRepresentation
bin1100000110001011110110…
…1111111100011010001001
31202002111122220020222000121
43001202331233330122021
53220403210431213231
644142042002303241
72541631236303163
oct301427557743211
952074586228017
1013300402210441
11426873a341715
1215a9859957b21
137562b7c20768
1433da58745933
15180e922e4311
hexc18bdbfc689

13300402210441 has 2 divisors, whose sum is σ = 13300402210442. Its totient is φ = 13300402210440.

The previous prime is 13300402210367. The next prime is 13300402210453. The reversal of 13300402210441 is 14401220400331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12973251385600 + 327150824841 = 3601840^2 + 571971^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300402210441 - 219 = 13300401686153 is a prime.

It is not a weakly prime, because it can be changed into another prime (13300402240441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650201105220 + 6650201105221.

It is an arithmetic number, because the mean of its divisors is an integer number (6650201105221).

Almost surely, 213300402210441 is an apocalyptic number.

It is an amenable number.

13300402210441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300402210441 is an equidigital number, since it uses as much as digits as its factorization.

13300402210441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13300402210441 its reverse (14401220400331), we get a palindrome (27701622610772).

The spelling of 13300402210441 in words is "thirteen trillion, three hundred billion, four hundred two million, two hundred ten thousand, four hundred forty-one".