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133004244124151 = 12011823252124097
BaseRepresentation
bin11110001111011101110110…
…101110011000000111110111
3122102221002012110100102001022
4132033131312232120013313
5114413120142443433101
61150513150051451355
740005145105342421
oct3617356656300767
9572832173312038
10133004244124151
1139419868438224
1212b011442b6b5b
13592a32846c84a
1424bb6229d5811
151059b2b6d5a1b
hex78f776b981f7

133004244124151 has 16 divisors (see below), whose sum is σ = 133246369221888. Its totient is φ = 132762405888000.

The previous prime is 133004244124117. The next prime is 133004244124189. The reversal of 133004244124151 is 151421442400331.

It is a cyclic number.

It is not a de Polignac number, because 133004244124151 - 226 = 133004177015287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133004244124651) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5519523335 + ... + 5519547431.

It is an arithmetic number, because the mean of its divisors is an integer number (8327898076368).

Almost surely, 2133004244124151 is an apocalyptic number.

133004244124151 is a deficient number, since it is larger than the sum of its proper divisors (242125097737).

133004244124151 is a wasteful number, since it uses less digits than its factorization.

133004244124151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29642.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 133004244124151 its reverse (151421442400331), we get a palindrome (284425686524482).

The spelling of 133004244124151 in words is "one hundred thirty-three trillion, four billion, two hundred forty-four million, one hundred twenty-four thousand, one hundred fifty-one".

Divisors: 1 1201 1823 2521 24097 2189423 3027721 4595783 28940497 43928831 60748537 5519535383 52758526031 72958992937 110744582951 133004244124151