Base | Representation |
---|---|
bin | 11110001111011110000010… |
… | …101110101110110001101011 |
3 | 122102221002201111100120111100 |
4 | 132033132002232232301223 |
5 | 114413121101024343111 |
6 | 1150513222044532443 |
7 | 40005153102361062 |
oct | 3617360256566153 |
9 | 572832644316440 |
10 | 133004445543531 |
11 | 394199610aa621 |
12 | 12b0119b851123 |
13 | 592a35b102c03 |
14 | 24bb6416671d9 |
15 | 1059b3e220756 |
hex | 78f782baec6b |
133004445543531 has 12 divisors (see below), whose sum is σ = 192472648045600. Its totient is φ = 88505730857520.
The previous prime is 133004445543461. The next prime is 133004445543581. The reversal of 133004445543531 is 135345544400331.
133004445543531 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 0 + 4 + 44 + 554 + 3 + 53 + 1 = 666.
It is not a de Polignac number, because 133004445543531 - 223 = 133004437154923 is a prime.
It is a super-2 number, since 2×1330044455435312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133004445543581) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 13658286931 + ... + 13658296668.
Almost surely, 2133004445543531 is an apocalyptic number.
133004445543531 is a deficient number, since it is larger than the sum of its proper divisors (59468202502069).
133004445543531 is a wasteful number, since it uses less digits than its factorization.
133004445543531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27316584146 (or 27316584143 counting only the distinct ones).
The product of its (nonzero) digits is 2592000, while the sum is 45.
Adding to 133004445543531 its reverse (135345544400331), we get a palindrome (268349989943862).
The spelling of 133004445543531 in words is "one hundred thirty-three trillion, four billion, four hundred forty-five million, five hundred forty-three thousand, five hundred thirty-one".
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