Base | Representation |
---|---|
bin | 111101111011110111… |
… | …0001101001111101011 |
3 | 110201022100120100110221 |
4 | 1323313232031033223 |
5 | 4134343301312412 |
6 | 141033544550511 |
7 | 12415663505551 |
oct | 1736756151753 |
9 | 421270510427 |
10 | 133005104107 |
11 | 51452a06347 |
12 | 2193b182437 |
13 | c708655345 |
14 | 661a63dbd1 |
15 | 36d6ab4b07 |
hex | 1ef7b8d3eb |
133005104107 has 2 divisors, whose sum is σ = 133005104108. Its totient is φ = 133005104106.
The previous prime is 133005104093. The next prime is 133005104207. The reversal of 133005104107 is 701401500331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133005104107 is a prime.
It is not a weakly prime, because it can be changed into another prime (133005104207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66502552053 + 66502552054.
It is an arithmetic number, because the mean of its divisors is an integer number (66502552054).
Almost surely, 2133005104107 is an apocalyptic number.
133005104107 is a deficient number, since it is larger than the sum of its proper divisors (1).
133005104107 is an equidigital number, since it uses as much as digits as its factorization.
133005104107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 25.
Adding to 133005104107 its reverse (701401500331), we get a palindrome (834406604438).
The spelling of 133005104107 in words is "one hundred thirty-three billion, five million, one hundred four thousand, one hundred seven".
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