Base | Representation |
---|---|
bin | 1100000110001100010100… |
… | …0110011011011101110011 |
3 | 1202002111222111100000200111 |
4 | 3001203011012123131303 |
5 | 3220403434014422311 |
6 | 44142102130002151 |
7 | 2541634264524133 |
oct | 301430506333563 |
9 | 52074874300614 |
10 | 13300525545331 |
11 | 42687a2a20a82 |
12 | 15a9893116357 |
13 | 75630764459b |
14 | 33da6ac8cac3 |
15 | 180e9d057d21 |
hex | c18c519b773 |
13300525545331 has 2 divisors, whose sum is σ = 13300525545332. Its totient is φ = 13300525545330.
The previous prime is 13300525545317. The next prime is 13300525545343. The reversal of 13300525545331 is 13354552500331.
13300525545331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13300525545331 - 215 = 13300525512563 is a prime.
It is a super-2 number, since 2×133005255453312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13300525545311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650262772665 + 6650262772666.
It is an arithmetic number, because the mean of its divisors is an integer number (6650262772666).
Almost surely, 213300525545331 is an apocalyptic number.
13300525545331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300525545331 is an equidigital number, since it uses as much as digits as its factorization.
13300525545331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405000, while the sum is 40.
The spelling of 13300525545331 in words is "thirteen trillion, three hundred billion, five hundred twenty-five million, five hundred forty-five thousand, three hundred thirty-one".
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