Base | Representation |
---|---|
bin | 10011010110101110011… |
… | …011000100010001101011 |
3 | 11201011010221122222112221 |
4 | 103112232123010101223 |
5 | 133242441213203301 |
6 | 2455005402214511 |
7 | 165044255606533 |
oct | 23265633042153 |
9 | 4634127588487 |
10 | 1330071225451 |
11 | 473097593a31 |
12 | 19593a1b4437 |
13 | 9856b169a77 |
14 | 485392544c3 |
15 | 248e8e1cda1 |
hex | 135ae6c446b |
1330071225451 has 2 divisors, whose sum is σ = 1330071225452. Its totient is φ = 1330071225450.
The previous prime is 1330071225419. The next prime is 1330071225473. The reversal of 1330071225451 is 1545221700331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330071225451 - 25 = 1330071225419 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330071925451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665035612725 + 665035612726.
It is an arithmetic number, because the mean of its divisors is an integer number (665035612726).
Almost surely, 21330071225451 is an apocalyptic number.
1330071225451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330071225451 is an equidigital number, since it uses as much as digits as its factorization.
1330071225451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 34.
Adding to 1330071225451 its reverse (1545221700331), we get a palindrome (2875292925782).
The spelling of 1330071225451 in words is "one trillion, three hundred thirty billion, seventy-one million, two hundred twenty-five thousand, four hundred fifty-one".
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