Base | Representation |
---|---|
bin | 1100000110001110000111… |
… | …1110100001001111111011 |
3 | 1202002120020020221102211021 |
4 | 3001203201332201033323 |
5 | 3220410432030324011 |
6 | 44142222153443311 |
7 | 2541652266441643 |
oct | 301434176411773 |
9 | 52076206842737 |
10 | 13301010011131 |
11 | 4268a21438337 |
12 | 15a99a9410537 |
13 | 756383b1ab3b |
14 | 33dab535d523 |
15 | 180eca853471 |
hex | c18e1fa13fb |
13301010011131 has 4 divisors (see below), whose sum is σ = 13301113200064. Its totient is φ = 13300906822200.
The previous prime is 13301010011123. The next prime is 13301010011137. The reversal of 13301010011131 is 13111001010331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13301010011131 - 23 = 13301010011123 is a prime.
It is a super-2 number, since 2×133010100111312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13301010011137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51400875 + ... + 51658996.
It is an arithmetic number, because the mean of its divisors is an integer number (3325278300016).
Almost surely, 213301010011131 is an apocalyptic number.
13301010011131 is a deficient number, since it is larger than the sum of its proper divisors (103188933).
13301010011131 is a wasteful number, since it uses less digits than its factorization.
13301010011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103188932.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 13301010011131 its reverse (13111001010331), we get a palindrome (26412011021462).
The spelling of 13301010011131 in words is "thirteen trillion, three hundred one billion, ten million, eleven thousand, one hundred thirty-one".
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