Base | Representation |
---|---|
bin | 11110001111100011010110… |
… | …111110111101111000000011 |
3 | 122102221122110022220220111112 |
4 | 132033203112332331320003 |
5 | 114413214243414144443 |
6 | 1150520004330033535 |
7 | 40005444420041144 |
oct | 3617432676757003 |
9 | 572848408826445 |
10 | 133010154053123 |
11 | 39421320439346 |
12 | 12b023135788ab |
13 | 592aa5a990239 |
14 | 24bba23879acb |
15 | 1059d7547ab18 |
hex | 78f8d6fbde03 |
133010154053123 has 2 divisors, whose sum is σ = 133010154053124. Its totient is φ = 133010154053122.
The previous prime is 133010154053111. The next prime is 133010154053159. The reversal of 133010154053123 is 321350451010331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133010154053123 - 24 = 133010154053107 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133010154053123.
It is not a weakly prime, because it can be changed into another prime (133010154055123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505077026561 + 66505077026562.
It is an arithmetic number, because the mean of its divisors is an integer number (66505077026562).
Almost surely, 2133010154053123 is an apocalyptic number.
133010154053123 is a deficient number, since it is larger than the sum of its proper divisors (1).
133010154053123 is an equidigital number, since it uses as much as digits as its factorization.
133010154053123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 32.
The spelling of 133010154053123 in words is "one hundred thirty-three trillion, ten billion, one hundred fifty-four million, fifty-three thousand, one hundred twenty-three".
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